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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousHard2 minPYQ_2020

PhysicsHardsingle choice

A spring executes S.H.M. with mass $10 kg$ attached to it. The force constant of the spring is $10 N / m$ . If at any instant its velocity is $40 cm / s$ , the displacement at that instant is (Amplitude of S.H.M. $= 0.5 m$ )

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Answer:

Solution:

$V = 0 A^{2} - x^{2} = \frac{k}{m} \cdot A^{2} - x^{2} k = 10 N / m, m = 10 kg, A = 0.5 m V = 40 cm / s = 0.4 m / s$ Substituting the values and solving we get $x = 0.3 m$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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