Physics - SHM Question with Solution | TestHub

Ans. (A, B, C) Force $|\mathrm{F}|=\mathrm{kx}$, zero at $\mathrm{x}=0$, $|\mathrm{a}|={\omega }^2\mathrm{x}$, maximum at $\mathrm{x}=\pm \mathrm{A}$. V is maximum at mean position, $\mathrm{x}=0$, $PE=KE$ at $x=\pm \frac{A}{\sqrt{2}}$

The force is zero at $x=0$, which occurs at $t=\frac{3T}{4}$. Acceleration is maximum at $x=\pm A$, which occurs at $t=T$. Velocity is maximum at $x=0$, which occurs at $t=\frac{T}{4}$. $PE=KE$ at $x=\pm \frac{A}{\sqrt{2}}$. Thus, options A, B, and C are correct.