A simple pendulum of length 1 m is allowed to oscillate with amplitude $4^{\circ}$ . It collides elastically with wall inclined at $2^{\circ}$ to the vertical. Its time period will be :- $($ Take $g = π^{2})$

Question

A simple pendulum of length 1 m is allowed to oscillate with amplitude 4 ∘ . It collides elastically with wall inclined at 2 ∘ to the vertical. Its time period will be :- ( Take g = π 2 )

TestHub · Accepted Answer

​ θ = 2 π ​ + 2 π ​ + 6 π ​ + 6 π ​ ​ θ = π + 3 π ​ = 3 4 π ​ ​ θ = ω t ​ 3 4 π ​ = ( T 2 π ​ ) t ​ ⇒ t = 3 2 T ​ = 3 2 ​ × 2 π g L ​ ​ ​ t = 3 2 ​ × 2 π π 2 1 ​ ​ = 3 4 ​ sec ​

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