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PhysicsSHMCalculation of time periodMedium2 minQB

PhysicsMediummultiple choice

The springs are identical and initially relaxed. The block is pushed to left and released.

Answer:

A, C

Solution:

Springs in parallel: $k_{e q} = k + k = 2 k$ , so $T = 2 π \frac{m}{2 k}$ .

If one spring is removed, $k_{e q} = k$ and $T = 2 π \frac{m}{k}$ , so T increases.

Hence (A) and (C).

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

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