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PhysicsSHMCalculation of time periodMedium2 minQB

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A second's pendulum is taken to a planet where the acceleration due to gravity is four times that on the earth. To keep the time period constant,

Answer:

Solution:

$T = 2 π l / g$

For constant $T$ , the length is proportional to $g$ .

With $g$ becoming $4 g$ , the length must become $4 l$ .

It should be made four times.

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

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