Physics - SHM Question with Solution | TestHub

The correct option is (D). Concept: For SHM $\frac{{\mathrm{d}}^2\mathrm{x}}{{\mathrm{dt}}^2}=-\left({\omega }^2\right)\mathrm{x}$ is the necessary condition, where $\omega$ is the angular frequency. On comparing with the given equation $\omega =\sqrt{\alpha }$ Therefore, the time period of the SHM is: $\mathrm{T}=\frac{2\pi }{\omega }=\frac{2\pi }{\sqrt{\alpha }}$