Physics - SHM Question with Solution | TestHub

Given $m=10$ kg, $k=10$ N/m, $v=40$ cm/s $=0.4$ m/s, and $A=0.5$ m.

The angular frequency of the spring-mass system is given by $\omega =\sqrt{\frac{k}{m}}=\sqrt{\frac{10}{10}}=1$ rad/s.

The velocity of a particle in S.H.M. is $v=\omega \sqrt{A^2-x^2}$.

Substituting the given values:

$0.4=1\times \sqrt{(0.5{)}^2-x^2}$

Squaring both sides:

$0.16=0.25-x^2$

$x^2=0.25-0.16=0.09$

$x=0.3$ m.

Answer: $0.3$ m