Physics - SHM Question with Solution | TestHub

The maximum potential energy of a linear harmonic oscillator is given by $U_{\text{max}}=\frac{1}{2}k{A}^2$.

Substituting the given values $k=2\times 10^6$ N/m and $A=0.01$ m:

$U_{\text{max}}=\frac{1}{2}\times (2\times 10^6)\times (0.01{)}^2$

$U_{\text{max}}=10^6\times 10^{-4}=100$ J.

The maximum kinetic energy is also equal to the maximum potential energy, which is $100$ J.

Answer: maximum potential energy is $100$ J.