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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The period of a simple pendulum inside a stationary lift is $T$ . The lift accelerates upwards with an acceleration of $g / 3$ . The time period of pendulum will be

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Answer:

Solution:

When lift accelerates upwards, then effective acceleration on the pendulum

$g_{e f f} = g + \frac{g}{3} = \frac{4 g}{3}$

$∴$ Time period $T^{'} = 2 π \sqrt{\frac{l}{g_{e f f}}} = 2 π \sqrt{\frac{l}{4 g / 3}}$

$= \frac{\sqrt{3}}{2} . 2 π \sqrt{\frac{l}{g}}$

$= \frac{\sqrt{3}}{2} T$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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