Physics - SHM Question with Solution | TestHub

Total energy of the simple pendulum is given as $E=0.02$ J.

Mass of the bob, $m=20$ g $=0.02$ kg.

At the equilibrium position, the potential energy is zero and the total energy is purely kinetic.

$E=\frac{1}{2}m{v}^2$

$0.02=\frac{1}{2}\times 0.02\times v^2$

$v^2=2$

$v=\sqrt{2}\approx 1.41$ m/s.

Answer: $1.41$ m/s