Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2019

PhysicsEasysingle choice

A particle executes simple harmonic motion with a period of $8 s$ and amplitude $4 cm$ . Its maximum speed in $cm / s$ , is

Answer:

Solution:

$T = 8 sec; A = 4 cm$ $T = \frac{2 π}{ω}$ or $ω = \frac{2 π}{8}$ or $v_{m a x} = A ω = 4 \times \frac{π}{4} = π cm s^{- 1}$

Stream:AIIMSSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2019

Loading discussions...