Physics - SHM Question with Solution | TestHub

Given $m=0.4$ kg, $F=0.4$ N, and $x=4$ cm $=0.04$ m.

The force constant $k$ is given by the relation $F=kx$.

$k=\frac{F}{x}=\frac{0.4}{0.04}=10$ N/m.

The magnitude of acceleration $a$ at this displacement is given by Newton's second law, $F=ma$.

$a=\frac{F}{m}=\frac{0.4}{0.4}=1$ m/s${}^2$.

Answer: $10{\text{N/}}_{\text{m}},1{\text{m/}}_{{\text{s}}^2}$