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PhysicsSHMEnergyMedium2 minQB

PhysicsMediumnumerical range

Particle of mass 1 kg is moving in S.H.M. on the x-axis and its potential and kinetic energy variation with position is as shown. Then the value of $x_{2} - x_{1}$ is given by :-

Answer:

8.45

Solution:

At $x_{1}$ and $x_{2}$ , KE = PE:

$\frac{1}{2} K (A^{2} - x^{2}) = \frac{1}{2} K x^{2} \Rightarrow x = \pm \frac{A}{2}$

$x_{1} = 2 - \frac{6}{2}, x_{2} = 2 + \frac{6}{2}$

$x_{2} - x_{1} = 2 \times \frac{6}{2} = 62 = 8.48$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: QB

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