Physics - SHM Question with Solution | TestHub

Maximum velocity in S.H.M. is given by $V=A\omega$, where $A$ is the amplitude and $\omega$ is the angular frequency.

The displacement of the particle from one extreme position to the other extreme position is $2A$.

The time taken to travel from one extreme to the other is half of the time period, which is $t=\frac{T}{2}=\frac{\pi }{\omega }$.

Average velocity is the ratio of total displacement to the total time taken.

$v_{avg}=\frac{2A}{\frac{\pi }{\omega }}=\frac{2A\omega }{\pi }$

Substituting $V=A\omega$, we get:

$v_{avg}=\frac{2V}{\pi }$

Answer: $\frac{2V}{\pi }$