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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

The displacement of the particle executing linear S.H.M. is $x = 0.25 sin (11 t + 0.5) m$ . The period of S.H.M. is $(π = \frac{22}{7})$

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Answer:

Solution:

Comparing with standard equation of S.H.M. $x = A sin (ω t + ϕ)$ we get $ω = 11$ $∴ T = \frac{2 π}{ω} = \frac{2 \times 22}{11 \times 7} = \frac{4}{7} κ$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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