Physics - SHM Question with Solution | TestHub

The time period of a mass suspended from a spring is given by $T=2\pi \sqrt{\frac{m}{k}}$.

For mass $m$, the time period is $T_1=2\pi \sqrt{\frac{m}{k}}=2\text{ s}$.

For mass $4m$, the time period is $T_2=2\pi \sqrt{\frac{4m}{k}}$.

$T_2=2\times 2\pi \sqrt{\frac{m}{k}}=2\times T_1$

$T_2=2\times 2=4\text{ s}$.

Answer: $4s$