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PhysicsSHMKinematicsMedium2 minPYQ_2024
PhysicsMediumnumerical

A particle executes simple harmonic motion with an amplitude of4 cm. At the mean position, velocity of the particle is10 cm s-1. The distance of the particle from the mean position when its speed becomes5 cm s-1isα cm, whereα=______.

Answer:
12.00
Solution:

The formula to calculate the velocity of the particle at the mean position is given by

V=Aω   ...1

From equation (1), it follows that

10=4×ωω=52 rad s-1

The formula to calculate the velocity of the particle at any instantaneous position x can be expressed as

v=ωA2-x2   ...2

From equation (2), it follows that

5=5242-x2x2=16-4=12x=12 cm

Hence, α=12.

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Kinematics
2mℹ️ Source: PYQ_2024

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