A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is 1 a s . The value

Question

A particle performs simple harmonic motion with a period of $2$ second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is $\frac{1}{a} s .$ The value of $a$ to the nearest integer is

Question diagram: A particle performs simple harmonic motion with a period of

Answer:

6.00

Solution:

$t = \frac{2}{12} = \frac{1}{6}$
$∴$ Correct answer $= 6.00$

TestHub · Accepted Answer

t = 2 12 = 1 6 ∴ Correct answer = 6 . 00

Physics - SHM Question with Solution | TestHub

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JEE Advanced (2027)