A particle of mass 0.50 kg executes simple harmonic motion under force F = − 50 ( Nm − 1 ) x . The time period of oscillation is 35 x s . The value of x is _______ (Given π = 7 22 )

Question

A particle of mass 0.50 kg executes simple harmonic motion under force F = − 50 ( Nm − 1 ) x . The time period of oscillation is 35 x ​ s . The value of x is _______ (Given π = 7 22 ​ )

TestHub · Accepted Answer

​ m = 0.5 kg F = − 50 ( x ) ma = ( − 50 x ) 0.5 a = − 50 x a = ( − 100 x ) W 2 = 100 ⇒ ( w = 10 ) T = 10 2 π ​ = ( 5 π ​ ) = 7 × 15 22 ​ = ( 35 22 ​ ) 35 π ​ = 35 22 ​ ⇒ x = 22 ​

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