Two simple harmonic motion, are represented by the equations
$y_{1} = 10 \sin (3 π t + \frac{π}{3}); y_{2} = 5 (\sin 3 π t + \sqrt{3} \cos 3 π t)$
Ratio of amplitude of $y_{1}$ to $y_{2} = x : 1$ . The value of $x$ is

Question

Two simple harmonic motion, are represented by the equations y 1 = 10 sin 3 π t + π 3 ; y 2 = 5 ( sin 3 π t + 3 cos 3 π t ) Ratio of amplitude of y 1 to y 2 = x : 1 . The value of x is

TestHub · Accepted Answer

y 1 = 10 sin 3 π t + π 3 y 2 = 5 [ sin 3 π t + 3 cos π t ] y 2 = 10 sin 3 π t + π 3 ⇒ A 2 A 1 = 10 10 = 1

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JEE Advanced (2027)