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PhysicsSHMCalculation of time periodEasy2 minPYQ_2023

PhysicsEasysingle choice

For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1 kg$ , the angular frequency is $ω_{1}$ . When the mass block is $2 kg$ the angular frequency is $ω_{2}$ . The ratio $\frac{ω_{2}}{ω_{1}}$ is :

Options:

Answer:

Solution:

In case of SHM in spring-block system, angular frequency is given by, $ω = \sqrt{\frac{k}{m}}$ .

Therefore,

$\frac{ω_{2}}{ω_{1}} = \sqrt{\frac{m_{1}}{m_{2}}} = \frac{1}{\sqrt{2}}$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2023

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