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PhysicsSHMEnergyMedium2 minQB

PhysicsMediuminteger

In a simple harmonic motion, the ratio of kinetic energy to potential energy at displacement half of the amplitude is

Answer:

Solution:

At displacement x = A/2: $P . E . = \frac{1}{2} k (\frac{A}{2})^{2} = \frac{1}{8} k A^{2}$

$K . E . = \frac{1}{2} k A^{2} - \frac{1}{8} k A^{2} = \frac{3}{8} k A^{2} \Rightarrow \frac{K . E .}{P . E .} = 3$ .

Answer: 3

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: QB

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