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PhysicsSHMCalculation of time periodHard2 minPYQ_2023

PhysicsHardsingle choice

A body of mass $0.04 kg$ excutes simple harmonic motion (SHM) about $x = 0$ under the influence of force $F$ as shown in graph. The period of

Answer:

Solution:

$k = 400 N / m m = 0.04$ From the graph, $K = \frac{F}{x} = \frac{8}{2} = 4$ From $T = 2 π \frac{M}{K}$ , we get $T = 2 π \frac{0.04}{4} = 0.2 π s$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2023

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