When two light waves each of amplitude 'A' and having a phase difference of 2 π superimposed then the amplitude of resultant wave is

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PhysicsSHMMiscellaneousEasy2 minPYQ_2023

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When two light waves each of amplitude 'A' and having a phase difference of $\frac{π}{2}$ superimposed then the amplitude of resultant wave is

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Solution:

The formula for resultant amplitude is, $R = A_{1}^{2} + A_{2}^{2} + 2 A_{1} A_{2} cos ϕ$ Here, $A_{1} = A_{2} = A$ and $ϕ = 9 0^{\circ}$ $∴ R = A^{2} + A^{2} + 2 A^{2} cos 9 0^{\circ} = 2 A^{2} = 2 A$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2023

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