Equation of simple harmonic progressive wave is given by y = a 1 sin ω t ± b 1 cos ω t then the resultant amplitude of the wave is ( cos 9 0 ∘ = 0 )

y = a 1 sin ω t ± b 1 sin ( ω t + 2 π ) Here phase difference = 2 π The resultant amplitude = ( a 1 ) 2 + ( b 1 ) 2 = a 1 + b 1 = ab a + b

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PhysicsSHMMiscellaneousHard2 minPYQ_2023

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Equation of simple harmonic progressive wave is given by $y = \frac{1}{a} sin ω t \pm \frac{1}{b} cos ω t$ then the resultant amplitude of the wave is $(cos 9 0^{\circ} = 0)$

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Solution:

$y = \frac{1}{a} sin ω t \pm \frac{1}{b} sin (ω t + \frac{π}{2})$ Here phase difference $= \frac{π}{2}$ The resultant amplitude $= (\frac{1}{a})^{2} + (\frac{1}{b})^{2} = \frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2023

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