Start Free Mock LoginAlready registered? Login here

Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousMedium2 minPYQ_2023

PhysicsMediumsingle choice

A simple pendulum performs simple harmonic motion about $x = 0$ with an amplitude ' $a$ ' and time period ' $T$ '. The speed of the pendulum at $x = \frac{a}{2}$ is

Options:

Answer:

Solution:

$v At x ∴ v ∴ v = ω a^{2} - x^{2} = \frac{a}{2}, = ω a^{2} - \frac{a ^{2}}{4} = ω \frac{3 a}{2} = \frac{2 π}{T} \times \frac{3 a}{2} = \frac{π a 3}{T}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2023

Doubts & Discussion

Loading discussions...