Physics - SHM Question with Solution | TestHub

Comparing with standard equation: $x=a\sin [\omega t+\varphi ]$ The amplitude of the wave is $a=5$ and the angular velocity of the wave is $\omega =4$ The velocity of the wave can be obtained by taking derivative as: $\begin{array}{rl}& \frac{dx}{dt}=\omega a\cos [\omega t+\varphi ]=\omega \sqrt{a^2-x^2}\\ & \therefore v=\omega \sqrt{a^2-y^2}=4\sqrt{(5{)}^2-(3{)}^2}=16\mathrm{cm}/\mathrm{s}\end{array}$