Time period of a simple pendulum in a stationary lift is $T$ . If the lift accelerates with $\frac{g}{6}$ vertically upwards then the time period will be
(Where $g =$ acceleration due to gravity)

Question

Time period of a simple pendulum in a stationary lift is T . If the lift accelerates with g 6 vertically upwards then the time period will be (Where g = acceleration due to gravity)

TestHub · Accepted Answer

The time period of a simple pendulum is given by T = 2 π l g In an upward accelerating frame the effective g e f f = g + a ⇒ T 2 = 2 π l g + a = 2 π l g + g 6 T T 2 = g + g 6 g = 7 6 ⇒ T 2 = 6 7 T

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