The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 1 0 − 2 cos π t metres. The time at which the maximum speed first occurs is

x = 2 × 1 0 − 2 cos π t v = − 0.02 π sin π t v is maximum at t = 2 1 = 0.5 sec

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PhysicsSHMKinematicsEasy2 minPYQ_2007

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The displacement of an object attached to a spring and executing simple harmonic motion is given by $x = 2 \times 1 0^{- 2} cos π t$ metres. The time at which the maximum speed first occurs is

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Answer:

Solution:

$x = 2 \times 1 0^{- 2} cos π t v = - 0.02 π sin π t$ $v$ is maximum at $t = \frac{1}{2} = 0.5 sec$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Kinematics

⏱ 2mℹ️ Source: PYQ_2007

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