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PhysicsSHMEnergyMedium2 minPYQ_2021
PhysicsMediumsingle choice

An object of mass0.5 kgis executing simple harmonic motion. It amplitude is5 cmand time period (T) is0.2 s. What will be the potential energy of the object at an instantt=T4 sstarting from mean position. Assume that the initial phase of the oscillation is zero.

Options:

Answer:
A
Solution:

T=2πmk

0.2=2π0.5k

k=50π2

500

x=Asin(ωt+ϕ)

=5 cmsinωT4+0

=5 cmsinπ2

=5 cm

PE=12kx2

=12(500)51002

=0.6255

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Energy
2mℹ️ Source: PYQ_2021

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