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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousMedium2 minPYQ_2021

PhysicsMediumsingle choice

A particle executing S.H.M starts from the mean position. Its amplitude is ' $A$ ' and time period ' $T$ ' At what displacement its speed is one-fourth of the maximum speed?

Options:

Answer:

Solution:

$V = ω A^{2} - x^{2} V_{m a x} = A ω ∴ A^{2} - x^{2} = \frac{A}{4} ∴ 16 A^{2} - 16 x^{2} = A^{2} ∴ 16 x^{2} = 15 A^{2} ∴ x^{2} = \frac{15}{16} A^{2} ∴ x = \frac{A 15}{4}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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