Two simple harmonic motions are represented by the equation y 1 = 0.1 sin ( 100 π t + 3 π ) and y 2 = 0.1 cos π t . The phase difference of the velocity of particle 1 w.r.t. the velocity of the particle 2 is

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PhysicsSHMKinematicsMedium2 minPYQ_2005

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Two simple harmonic motions are represented by the equation $y_{1} = 0.1$ $sin (100 π t + \frac{π}{3})$ and $y_{2} = 0.1 cos π t$ . The phase difference of the velocity of particle 1 w.r.t. the velocity of the particle 2 is

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Solution:

Phase difference $(ϕ) = 99 π t + π /3 - π /2$ at $t = 0, ϕ = - π /6$ .

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Kinematics

⏱ 2mℹ️ Source: PYQ_2005

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