A bob of simple pendulum of mass 'm' perform SHM with amplitude ' A ' and period ' T '. Kinetic energy of pendulum at displacement x = 2 A will be

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A bob of simple pendulum of mass 'm' perform SHM with amplitude ' A ' and period ' T '. Kinetic energy of pendulum at displacement x = 2 A ​ will be

TestHub · Accepted Answer

​ Kinetic energy = 2 1 ​ m ω 2 ( A 2 − x 2 ) At x = 2 A ​ , K.E. = 2 1 ​ m ω 2 ( 4 3 ​ A 2 ) = 8 3 ​ m ω 2 A 2 = 8 3 ​ m ( T 2 π ​ ) 2 ⋅ A 2 = 8 3 ​ m T 2 4 π 2 ​ ⋅ A 2 = 2 T 2 3 m π 2 A 2 ​ ​

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