A small disc is performing angular oscillation with a wire of torsional constant k, with an angular amplitude θ 0 . When it passes through half of its amplitude , a sharp angular impulse is provided

Question

A small disc is performing angular oscillation with a wire of torsional constant k, with an angular amplitude θ 0 ​ . When it passes through half of its amplitude , a sharp angular impulse is provided, so that its, angular velocity increases to 1.5 times of the angular velocity of same position. Find its new angular amplitude:

TestHub · Accepted Answer

Using analogy \displaylines v 2 = ω 2 ( A 2 − x 2 ) ( 2 3 ​ v ) 2 = ω 2 ( A 2 1 ​ − ( 2 A ​ ) 2 ) A 1 ​ = 4 A ​ 31 ​ θ 1 ​ = 4 θ 0 ​ ​ 31 ​

Physics - SHM Question with Solution | TestHub

Options:

Doubts & Discussion

JEE Main (2026)

JEE Advanced (2027)