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PhysicsSHMMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

A disc of radiusRand massMis pivoted at the rim and is set for small oscillations. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum should be

Options:

Answer:
D
Solution:



τ=-mgRsin⁡θ=-mgRθ   ∵sin⁡θ≃θ

Iα =12mR2+mR2α=32mR2α

Butτ= Iα

32mR2α=-mgRθ

α=-2g3Rθ=ω2θ

Time periodT=2π3R2g

For simple pendulum,T=2πlg

l=3R2

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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