Physics - SHM Question with Solution | TestHub

$\text{When}\text{t}=2\text{s}\text{,}\text{y}=\frac{\sqrt{3}}{2}\text{r}$

Now, y = r sin ωt

$\therefore \frac{\sqrt{3}}{2}\text{r}=\text{r}\text{sin}\omega \times 2\text{or}\text{sin}2\omega =\frac{\sqrt{3}}{2}$

$\text{or}2\omega =\frac{\text{π}}{3}\text{or}\omega =\frac{\text{π}}{6}$

$\text{Hence,}\text{T}=\frac{2\text{π}}{\text{ω}}=\frac{2\text{π}}{\text{π}\mathrm{/6}}=12\text{s}$