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Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle executes a simple harmonic motion of time period $T$ . Find the time taken by the particle to go directly from its mean position to half the amplitude.

Options:

Answer:

Solution:

$y = A \sin ω t = A \sin (\frac{2 π}{T} t)$
$\Rightarrow \frac{A}{2} = A \sin (\frac{2 π t}{T})$
$\Rightarrow t = \frac{T}{12}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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