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Physics - SHM Question with Solution | TestHub

PhysicsSHMOscillations and SHMHard2 min

PhysicsHardmultiple choice

A spring of constant $K$ is fixed to the ceiling of a lift with a block $m$ in equilibrium. The lift now accelerates downwards at $g /2$ . Select the correct statement(s).

Options:(select one or more)

Answer:

A, B

Solution:

$g_{e ff} = g /2$ downward, so the equilibrium extension is $\frac{m g}{2 K}$ . Start was $\frac{m g}{K}$ , so $A = \frac{m g}{2 K}$ . The spring never reaches natural length, so min P.E. is not 0.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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