Physics - SHM Question with Solution | TestHub

$\mathrm{T}=2\pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}$ $\therefore$ When the trolley has 18. (A) $\frac{f_1}{24}=\frac{1.5-1}{\frac{1.5}{9/8}-1}=\frac{0.5}{\frac{1.5}{1.16}-1}=\frac{0.5\times 1.16}{0.34}$ ${\mathrm{f}}_1=24\times \frac{1}{2}\times \frac{1.16}{0.34}=\frac{12\times 1.16}{0.34}=40.94\mathrm{cm}$ acceleration is the resultant of $\mathrm{a}$ and ${\mathrm{g}}_{\mathrm{W}}$ where $g$ is the effective value of acceleration due to gravity. $\mathrm{a}$ ' in horizontal direction, the effective value $=$ are at right angles to each other. Hence $\begin{array}{rl}\therefore T& =2\pi \sqrt{\frac{L}{{\left(a^2+g^2\right)}^{\frac{1}{2}}}}=\frac{2\pi \sqrt{L}}{\sqrt{{\left(a^2+g^2\right)}^{\frac{1}{2}}}}\\ & =2\pi \sqrt{L}{\left(a^2+g^2\right)}^{-\frac{1}{4}}\end{array}$