An object of mass 1 kg executes simple harmonic oscillations along the x -axis with a frequency of 2 π H z . At the position x = 1 m , the object has a kinetic energy of 24 J . The amplitude of the oscillation is

K . E . = 1 2 mω 2 A 2 - x 2 = 24 J 1 2 × 1 × 16 A 2 - 1 = 24 A = 2 m

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PhysicsSHMEnergyEasy2 minPYQ_2020

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An object of mass $1 kg$ executes simple harmonic oscillations along the $x$ -axis with a frequency of $\frac{2}{π} H z$ . At the position $x = 1 m$ , the object has a kinetic energy of $24 J$ . The amplitude of the oscillation is

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Answer:

Solution:

$K . E . = \frac{1}{2} {mω}^{2} (A^{2} - x^{2}) = 24 J$

$\frac{1}{2} \times 1 \times 16 (A^{2} - 1) = 24$

$A = 2 m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: PYQ_2020

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