The equation of simple harmonic wave is given as y = 5 sin 2 π ( 100 t − x ) , where ' x ' and ' y ' are in metre and time in second. The period of the wave is

(B) y = 5 sin 2 π ( 100 t − x ) y = Asin ( ω t − kx ) ω = T 2 π T = 100 2 π ⇒ T = 0.06 Hence, the correct option is (B)

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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

The equation of simple harmonic wave is given as $y = 5 sin \frac{π}{2} (100 t - x)$ , where ' $x$ ' and ' $y$ ' are in metre and time in second. The period of the wave is

Options:

Answer:

Solution:

(B) $y = 5 sin \frac{π}{2} (100 t - x) y = Asin (ω t - kx) ω = \frac{2 π}{T} T = \frac{2 π}{100} \Rightarrow T = 0.06$ Hence, the correct option is (B)

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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