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Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle moves such that its acceleration is given by

$a = - β (x - 2)$

Here : $β$ is a positive constant and $x$ is the position from origin. Time period of oscillations is

Options:

Answer:

Solution:

$a = - β (x - 2)$

as $a = - ω^{2} (x - x_{0})$

by comparing

$ω^{2} = β$

$\Rightarrow T = 2 π \sqrt{\frac{1}{β}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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