The potential energy of a simple harmonic oscillator of mass = 2 kg in its mean position is 5 J . If its total energy is 9 J and its amplitude is 0 . 01 m , its time period would be:

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P . E . = 5 J , T . E . = 9 J Using mechanical energy conservation T . E . = P . E . + K . E . 9 = 5 + K . E . ⇒ K . E . = 4 (Maximum) K . E . m a x at mean position = 1 2 ω 2 A 2 m 4 = 1 2 × 2 × 2 π t 2 × 1 100 × 1 100 T 2 = π 2 100 × 100 T = π 100 s

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