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Physics - SHM Question with Solution | TestHub

PhysicsSHMEnergyEasy2 minPYQ_2020

PhysicsEasysingle choice

A simple pendulum of length 'L' has mass 'm' and it oscillates freely with amplitude 'A' At extreme position, its potential energy is (g =acceleration due to gravity)

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Answer:

Solution:

$PE = \frac{m ω ^{2} x ^{2}}{2}$ $ω = \frac{g}{L}$ , at extreame point $x = A$ So $PE = \frac{MgA ^{2}}{2 L}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: PYQ_2020

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