Time period of a simple pendulum is T . The time taken to complete 5 8 oscillations starting from mean position is α 12 T . The value of α is _ _ _ _ _ _ .

5 8 th of oscillation = 1 2 + 1 8 th of oscillation π + θ = ω t π + π 6 = 2 π T t 7 π 6 = 2 π T t t = 7 T 12

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PhysicsSHMMiscellaneousMedium2 minPYQ_2021

PhysicsMediumnumerical

Time period of a simple pendulum is $T$ . The time taken to complete $\frac{5}{8}$ oscillations starting from mean position is $\frac{α}{12} T$ . The value of $α$ is $______$ .

Answer:

7.00

Solution:

$\frac{5}{8}$ th of oscillation $= {(\frac{1}{2} + \frac{1}{8})}^{th}$ of oscillation
$π + θ = ω t$
$π + \frac{π}{6} = (\frac{2 π}{T}) t$
$\frac{7 π}{6} = (\frac{2 π}{T}) t$
$t = \frac{7 T}{12}$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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