Physics - SHM Question with Solution | TestHub

A harmonic oscillation of constant amplitude and of single frequency is called simple harmonic oscillation.

Here,$x=8\sin \omega t+6\cos \omega t$

So,$a_1=8 \mathrm{c}\mathrm{m}\mathrm{ }\mathrm{ }\mathrm{a}\mathrm{n}\mathrm{d} { a}_2=6 \mathrm{c}\mathrm{m}$

$\therefore$Amplitude of motion

$A=\sqrt{a_1^2+a_2^2}$

=$\sqrt{8^2+6^2}$

=$\sqrt{64+36}= \sqrt{100}=10 \mathrm{c}\mathrm{m}$