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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2021

PhysicsEasysingle choice

The displacement of a particle performing S.H.M is given by $x = 5 sin (3 t + 3)$ , where $x$ is in $cm$ and $t$ is in second. The maximum acceleration of the particle will be

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Solution:

$x = 5 sin (3 t + 3)$ Standard equation of S.H.M. is $x = A sin (ω t + α)$ $∴ A = 5 cm, ω = 3 rad / s$ Maximum acceleration $a_{m} = A ω^{2} = 5 \times (3)^{2}$ $= 5 \times 9 = 45 cm s^{- 2}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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