Start Free Mock LoginAlready registered? Login here

Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodMedium2 minPYQ_2020

PhysicsMediumsingle choice

The period of seconds pendulum on a planet, whose mass and radius are three times that of earth, is

Options:

Answer:

Solution:

$\frac{g ^{'}}{g} \frac{T ^{'}}{T} ∴ T^{'} = \frac{M ^{'}}{M} \cdot \frac{R ^{2}}{R ^{'2}} = 3 \cdot \frac{1}{3 ^{2}} = \frac{1}{3} = \frac{g}{g ^{'}} = 3 = 3 T = 3 \cdot 2 second$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...