Physics - SHM Question with Solution | TestHub

$g_{eff}$at height of h

$g_{eff}=\frac{g}{{\left(1+\frac{h}{R_e}\right)}^2}=\frac{g{R}_e^2}{{\left({\mathrm{R}}_e+h\right)}^2}$

$\Rightarrow T=2T_1\sqrt{\frac{l}{g}}=2T_1\sqrt{\frac{l{\left(R_e+h\right)}^2}{R_e^2}}$

$\Rightarrow \frac{T_2\alpha }{T_1}\frac{R_e+h}{R_e}=\frac{6400+64}{6400}$

$\Rightarrow \frac{T_2}{T_1}=\left(1+\frac{1}{100}\right)$

$\therefore$Time period will increase by 1%.