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PhysicsSHMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A uniform spring of normal length $l$ has a force constant $k$ . It is cut into two pieces of length $l_{1}$ and $l_{2}$ such that $l_{1} = n l_{2}$ where $n$ is an integer. Then the value of $k_{1}$ (force constant of spring of length $l_{1}$ ) is-

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Answer:

Solution:

Using the relation kx = constant

$k_{1} l_{1} = k_{2} l_{2} = k (l_{1} + l_{2})$

$k_{1} = \frac{k (l_{1} + l_{2})}{l_{1}}$ or $k_{1} = \frac{k (n l_{2} + l_{2})}{n l_{2}}$

or $k_{1} = \frac{k (n + 1)}{n}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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